mohon bantuannya kakak2
Penjelasan dengan langkah-langkah:
[tex]\cos A = \frac{-3}{5}[/tex]
[tex]\boxed{\sin A = \frac{4}{5}}[/tex]
[tex]\sin B = \frac{5}{13}[/tex]
[tex]\boxed{\cos B = \frac{12}{13}}[/tex]
[tex]\begin{aligned} \sin(A + B) & = (\sin A × \cos B) + (\cos A × \sin B) \\ & = \frac{4}{5} × \frac{12}{13} + \frac{-3}{5} × \frac{5}{13} \\ & = \frac{4 × 12}{5 × 13} - \frac{3}{\cancel{5}} × \frac{\cancel{5}}{13} \\ & = \frac{48}{65} - 3\frac{1}{13} \\ & = \frac{48}{65} - \frac{3}{13} \\ & = \frac{48}{65} - \frac{3 × 5}{13 × 5} \\ & = \frac{48}{65} - \frac{15}{65} \\ & = \frac{48 - 15}{65} \\ & = \frac{33}{65} \end{aligned}[/tex]
Jadi nilai dari sin(A+B) adalah 33/65.
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